Regular Expression Powerfull sample in java
We can use regular expression and to do large set of works as simple and single line code .
In this example i will show you how the regular expression play a vital stage .
I want to read a file and insert a new line (\n) at every 100 th character in that file content and write those changes in another file.
Normally what i did first is written a code to read file line by line and written a sample piece of code to read position and insert the new line in that particular position then written in new file.
Instead for write separate function i write an replaceAll with regular expression.
The sample code given below,
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.File;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
public class REPower {
public static void main(String[] args) {
new REPower().replace();
}
public void replace() {
String oldFileName = "abc.txt";
String tmpFileName = "abcnew.txt";
BufferedReader br = null;
BufferedWriter bw = null;
try {
br = new BufferedReader(new FileReader(oldFileName));
bw = new BufferedWriter(new FileWriter(tmpFileName));
String line;
while ((line = br.readLine()) != null) {
line = line.replaceAll("(.{100})", "$1\n"); // Here is the code it simplefied that largest code in single
bw.write(line);
}
} catch (Exception e) {
return;
} finally {
try {
if(br != null)
br.close();
} catch (IOException e) {
// handle code
}
try {
if(bw != null)
bw.close();
} catch (IOException e) {
// handle code
}
}
// Once everything is complete, delete old file..
File oldFile = new File(oldFileName);
oldFile.delete();
// And rename tmp file's name to old file name
File newFile = new File(tmpFileName);
newFile.renameTo(oldFile);
}
}
In this example i will show you how the regular expression play a vital stage .
I want to read a file and insert a new line (\n) at every 100 th character in that file content and write those changes in another file.
Normally what i did first is written a code to read file line by line and written a sample piece of code to read position and insert the new line in that particular position then written in new file.
Instead for write separate function i write an replaceAll with regular expression.
The sample code given below,
package com.shinnedhawks;
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.File;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
public class REPower {
public static void main(String[] args) {
new REPower().replace();
}
public void replace() {
String oldFileName = "abc.txt";
String tmpFileName = "abcnew.txt";
BufferedReader br = null;
BufferedWriter bw = null;
try {
br = new BufferedReader(new FileReader(oldFileName));
bw = new BufferedWriter(new FileWriter(tmpFileName));
String line;
while ((line = br.readLine()) != null) {
line = line.replaceAll("(.{100})", "$1\n"); // Here is the code it simplefied that largest code in single
bw.write(line);
}
} catch (Exception e) {
return;
} finally {
try {
if(br != null)
br.close();
} catch (IOException e) {
// handle code
}
try {
if(bw != null)
bw.close();
} catch (IOException e) {
// handle code
}
}
// Once everything is complete, delete old file..
File oldFile = new File(oldFileName);
oldFile.delete();
// And rename tmp file's name to old file name
File newFile = new File(tmpFileName);
newFile.renameTo(oldFile);
}
}
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